Questions & Answers

Q1(a).
Short Answer 1 mark

The list below shows some SI quantities. Underline the quantity that is not an SI base quantity . charge current length time

Q1(b).
Short Answer 1 mark

A square solar panel with sides of length 1300 mm is shown in Fig. 1.1. 1300 mm 1300 mm solar panel incident light Fig. 1.1 (not to scale) Light is incident normally on the solar panel.

Q1(i).
Short Answer 3 marks

The power of the light incident on the solar panel is 750 W. Calculate the intensity of the light. intensity = W m

Q1(ii).
Short Answer 1 mark

The percentage uncertainty in the incident power is ± 3%. The uncertainty in the length of each side is ± 5 mm. Calculate the percentage uncertainty in the intensity of the light. percentage uncertainty = % [2] * 0019655340104 *

Q1(iii).
Short Answer 1 mark

The useful power output of the solar panel is 160 W. Calculate the percentage efficiency of the solar panel. efficiency = %

Q1(iv).
Short Answer 1 mark

Another square solar panel is placed so that light of the same intensity is incident normally on it. The new panel has shorter sides than the original panel. The new panel has the same power output as the original panel. State and explain whether the efficiency of the new panel is greater than, less than or the same as the efficiency of the original panel. [Total: 10] * 0019655340105 *

Q2.
Short Answer 1 mark

A skydiver jumps from an aircraft at time t = 0 and falls vertically downwards. The variation with t of her velocity v is shown in Fig. 2.1. 0 5 10 15 20 25 30 t / s v / m s

Q2(a).
Short Answer 1 mark

(i) Using Fig. 2.1, state the terminal velocity of the skydiver. terminal velocity = m s

Q2(ii).
Short Answer 1 mark

By drawing a suitable line on Fig. 2.1, determine the acceleration of the skydiver at time t = 9.0 s. acceleration = m s [2] * 0019655340106 *

Q2(b).
Short Answer 3 marks

The mass of the skydiver and her equipment is 68 kg. The upthrust on the skydiver is negligible. After reaching terminal velocity , the skydiver opens her parachute at time t . A total drag force of 1800 N acts on the skydiver. Determine the magnitude and direction of the acceleration of the skydiver at time t acceleration = m s direction =

Q2(c).
Short Answer 1 mark

The parachute is fully open at time t . At a later time t the skydiver reaches a constant velocity of 5.7 m s

Q2(i).
Short Answer 1 mark

Describe and explain the variation with time of the magnitude of her acceleration between time t and time t

Q2(ii).
Short Answer 1 mark

Calculate the change in momentum of the skydiver between time t and time t change in momentum = N s [2] [Total: 10] * 0019655340107 *

Q3.
Short Answer 1 mark

Lightning occurs when charge builds up in the atmosphere, creating a potential dif ference between the ground and the atmosphere. During a lightning strike there is an average current of 3.3 × 10 A for a time of 2.6 × 10

Q3(a).
Short Answer 2 marks

Calculate the charge transferred during the lightning strike. charge = C

Q3(b).
Short Answer 2 marks

The potential difference between the ground and the atmosphere is 3.0 × 10 Calculate the average power , in GW, transferred during the lightning strike. power = GW

Q3(c).
Short Answer 1 mark

A lightning rod is attached to a tall building to conduct charge safely to the ground. The lightning rod is modelled as a uniform cylindrical copper cable of total length 95 m that runs from the ground to the top of the building, as shown in Fig. 3.1. building ground lightning rod Fig. 3.1 * 0019655340108 *, ,

Q3(i).
Short Answer 3 marks

The resistance of the lightning rod is 9.6 Ω. The resistivity of copper is 1.7 × 10 Ω m. Determine the radius of the lightning rod. radius = m

Q3(ii).
Short Answer 1 mark

The radius of the copper lightning rod is doubled with no change to its length. State the effect of this change on the resistance of the lightning rod.

Q3(d).
Short Answer 1 mark

A section of the lightning rod of length 0.12 m is removed for testing. A tensile stress of 1.9 × 10 Pa is applied, as shown in Fig. 3.2. lightning rod tensile stress 1.9 × 10 0.12 m fixed support Fig. 3.2 (not to scale) The section of the rod obeys Hooke' s law. The Young modulus of copper is 1.3 × 10Pa. Calculate the extension of the section. extension = m [3] [Total: 11] * 0019655340209 *

Q4.
Short Answer 1 mark

A pinball machine uses a spring to launch a small metal ball of mass 4.5 × 10 kg up a ramp. The spring is compressed by 8.0 × 10 m and held in equilibrium, as shown in Fig. 4.1.15° original length fixed end spring horizontal ramp ball, mass 4.5 × 10 8.0 × 10 Fig. 4.1 (not to scale) The ramp is at an angle of 15° to the horizontal.

Q4(a).
Short Answer 2 marks

The spring obeys Hooke's law and has a spring constant of 29 N m Calculate the elastic potential energy in the compressed spring. elastic potential energy = J

Q4(b).
Short Answer 1 mark

The spring is released and expands quickly back to its original length.

Q4(i).
Short Answer 1 mark

Calculate the increase in gravitational potential energy of the ball when the spring returns to its original length. increase in gravitational potential energy = J [3] * 0019655340210 *

Q4(ii).
Short Answer 3 marks

The ball leaves the spring when the spring reaches its original length. Assume that all the elastic potential energy of the spring is transferred to the ball. Calculate the speed of the ball as it leaves the spring. speed = m s

Q4(c).
Short Answer 1 mark

The ball comes to rest on a horizontal trapdoor of negligible mass at a distance d from its pivot. A force F acts vertically downwards at a distance of 2.0 cm from the pivot, as shown in Fig. 4.2. 2.0 cm d F pivot trapdoor ball Fig. 4.2 (not to scale)

Q4(i).
Short Answer 2 marks

The trapdoor is in equilibrium when F is 1.7 N. Calculate d. d = m

Q4(ii).
Short Answer 1 mark

Force F is decreased from 1.7 N. State the direction of the resultant moment about the pivot on the trapdoor. [Total: 11] * 0019655340211 *

Q5(a).
Short Answer 1 mark

State Kirchhoff's second law.

Q5(b).
Short Answer 1 mark

A battery of electromotive force (e.m.f.) 9.0 V and negligible internal resistance is connected in series with a variable resistor X and a thermistor Y as shown in Fig. 5.1. 9.0 V Fig. 5.2 shows the relationship between temperature and resistance for the thermistor . 1000 200 300 400 resistance / Ω temperature / °C Fig. 5.2 * 0019655340212 *

Q5(i).
Short Answer 2 marks

The current in the circuit is 1.1 × 10 A. The potential difference across Y is 4.0 V. Calculate the resistance of X. resistance = Ω

Q5(ii).
Short Answer 3 marks

The temperature of Y is changed to 190 °C. The resistance of X remains unchanged. Determine the new potential difference across Y. potential difference = V

Q5(iii).
Short Answer 1 mark

The resistance of X is increased. The temperature of Y remains at 190 °C. By reference to the current in the circuit, state and explain the ef fect of this change, if any, on the potential difference across Y. [Total: 9] * 0019655340213 *

Q6.
Short Answer 1 mark

Light of a single frequency is incident normally on a dif fraction grating. An interference pattern of bright and dark fringes forms on the semicircular screen shown in Fig. 6.1. light semicircular screen diffraction grating Fig. 6.1 (not to scale) The light has wavelength 520 nm. The separation of the lines in the grating is 3.8 × 10

Q6(a).
Short Answer 1 mark

Determine the total number of bright fringes formed on the screen. number of bright fringes = [3] * 0019655340214 *

Q6(b).
Short Answer 1 mark

The light is replaced with red light of a single frequency .

Q6(i).
Short Answer 1 mark

State whether the frequency of the red light is greater than, less than or the same as the frequency of the original light.

Q6(ii).
Short Answer 1 mark

State and explain the effect of this change on the number of bright fringes formed on the screen. A calculation is not required. [Total: 6] * 0019655340215 * Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable ef fort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included, the publisher will be pleased to make amends at the earliest possible opportunity. To avoid the issue of disclosure of answer-related information to candidates, all copyright acknowledgements are reproduced online in the Cambridge Assessment International Education Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download at www.cambridgeinternational.org after the live examination series. Local Examinations Syndicate (UCLES), which is a department of the University of Cambridge.

Q7.
Short Answer 1 mark

A particle Q and a particle R are each composed of one quark and one antiquark.

Q7(a).
Short Answer 1 mark

State the name of the class (group) of particles that includes Q and R.

Q7(b).
Short Answer 1 mark

Q has a charge of ±1e, where e is the elementary charge. R has a charge of 0. Complete Table 7.1 to show a possible second quark in each of Q and R. Table 7.1 charge first quark second quark Q ±1e strange R 0 anti-up [2] [Total: 3] * 0019655340216 *